Python Program to Check Leap Year
Python Program to see Leap-year |
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A Leap-year is strictly divisible by 4 apart from century years (years ending with 00). The century year may be a Leap-year as long as it’s perfectly divisible by 400. for instance ,2017 isn’t a Leap-year 1900 may be a not Leap-year2012 may be a Leap-year 2000 may be a Leap-year | |
CODE | OUTPUT |
# Python program to check if the input year is a leap year or not
year = 2000
# To get year (integer input) from the user # year = int(input(“Enter a year: “))
if (year % 4) == 0: if (year % 100) == 0: if (year % 400) == 0: print(“{0} is a leap year”.format(year)) else: print(“{0} is not a leap year”.format(year)) else: print(“{0} is a leap year”.format(year)) else: print(“{0} is not a leap year”.format(year))
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2000 is a leap year
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You can change the value of year in the code and run it again to test this program. |